A pharmaceutical laboratory technician inspects 150, transparent, one-liter bottles of vaccines and records the number of suspended particles visible to the naked eye in each. The resulting frequencies are recorded in the table below where Lambda = 1.4. Using the Chi-Square test, test the claim that the data is Poisson distributed.
Suspended particles per liter | 0 | 1 | 2 | 3 | 4 | 5+ | Total |
Frequency | 33 | 44 | 42 | 21 | 8 | 2 | 150 |
Ans:
Suspended particles per liter,x | 0 | 1 | 2 | 3 | 4 | 5+ | Total |
Observed Frequency(fo) | 33 | 44 | 42 | 21 | 8 | 2 | 150 |
p(x)=Poisson(x,1.4,false) | 0.2466 | 0.3452 | 0.2417 | 0.1128 | 0.0395 | 0.0143 | 1 |
Expected frequency(fe) | 36.99 | 51.79 | 36.25 | 16.92 | 5.92 | 2.14 | 150 |
(fo-fe)^2/fe | 0.430 | 1.170 | 0.912 | 0.986 | 0.730 | 0.009 | 4.238 |
Test statistic:
Chi square=4.238
df=6-1=5
p-value=CHIDIST(4.238,5)=0.5157
Fail to reject the null hypothesis.
There is not sufficient evidence to reject the claim that the data is Poisson distributed..
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