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Find the value of E, the margin of error, for c = 0.90, n = 16...

Find the value of E, the margin of error, for c = 0.90, n = 16 and s = 2.2.

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Answer #1

b )Given that,

s =2.2

n = 16

Degrees of freedom = df = n - 1 =16 - 1 = 15

At 90% confidence level the t is ,

= 1 - 90% = 1 - 0.90 = 0.1

/ 2 = 0.1 / 2 = 0.05

t /2,df = t0.05,15 =    ( using student t table)

Margin of error = E = t/2,df * (s /n)

= 1.753 * ( 2.2/ 16) = 0.964

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