Question

An experiment shows that a 262 mL gas sample has a mass of 0.439 g at a pressure of 765 mmHg and a temperature of 32 ∘C.

Answer 1

Here

In this question there is no information about what we have to find.

So usually we find molar mass of the gas for this question so I posted the answer for that.

Given

Volume = 262 mL

Mass = 0.439g

Pressure = 765 mmHg

Temperature = 32⁰C = 32 + 273 = 305 K

Here

we have to convert the pressure into atm

Pressure (in atm) = 765 / 760 = 1.0066 atm

Formula :

PV = nRT

n = (mass of gas / Molar mass)

PV = (mass of gas / Molar mass) * RT

Molar mass = (mass of gas / PV ) * RT

= ( 0.439 / 1.0066 *0.262 ) * 0.08206 * 305 K

= 41.66 g/mol