In a sample of 100 households, the mean number of hours spent on social networking sites during the month of January was 50 hours. In a much larger study, the standard deviation was determined to be 6 hours. Assume the population standard deviation is the same. What is the 98% confidence interval for the mean hours devoted to social networking in January?
A |
The 98% confidence interval ranges from 6 to 50 hours. |
B |
The 98% confidence interval ranges from 48.60 to 51.40 hours. |
C |
The 98% confidence interval ranges from 49.40 to 50.60 hours. |
D |
The 98% confidence interval ranges from 50 to 52 hours. |
98% confidence interval for is
- Z/2 * / Sqrt(n) < < + Z/2 * / Sqrt(n)
50 - 2.3263 * 6 / sqrt(100) < < 50 + 2.3263 * 6 / sqrt(100)
48.60 < < 51.40
The 98% confidence interval ranges from 48.60 to 51.40 hours
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