Question

The average score of all golfers for a particular course has a mean of 73 and a standard deviation of 5. Suppose 100 golfers played the course today. Find the probability that the average score of the 100 golfers exceeded 74. Round to four decimal places.

Answer #1

Solution :

Given that,

mean = = 73

standard deviation = =5

n=100

= =73

= / n = 5/ 100 = 0.5

P( > 74) = 1 - P( < 74)

= 1 - P[( - ) / < (74-73) /0.5 ]

= 1 - P(z < 2)

Using z table

= 1 - 0.9772

probability= 0.0228

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