Question

Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. ​95% confidence; nequals=​2388, xequals=1672

Answer 1

Solution :

Given that,

n = 2388

x = 1672

Point estimate = sample proportion = = x / n = 1672/2388 = 0.700

1 - = 1 - 0.700 = 0.300

Z_/2 = 1.96

Margin of error = E = Z _{/ 2} * (( * (1 - )) / n)

= 1.96 * ((0.700(1- 0.700) /2388 )

= 0.018