A survey was taken of 383 students that asked the question how much time they spent watching television in a day (in minutes). Suppose this sample study follows a Normal distribution with a sample mean x-bar = 118 minutes. Also suppose the population has a standard deviation σ = 53 minutes. Determine a 96% confidence interval for the mean television watching time.
A. 112.67 to 123.31
B. 117.86 to 118.14
C. 112.44 to 123.56
D. 111.70 to 124.30
Since , the population standard deviation is known.
Therefore , use normal distribution.
Now , ; From standard normal distribution table
Therefore , the
96% confidence interval for the mean television watching time is ,
Correct option s (C)
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