Question

The results of a one-way ANOVA are reported below. Source of variation SS df MS F...

  1. The results of a one-way ANOVA are reported below.

Source of variation

SS

df

MS

F

Between groups

7.18

3

2.39

21.73

Within groups

48.07

453

0.11

Total

55.25

456
  1. How many treatments are there in the study?
  2. What is the total sample size?
  3. What is the critical value of F if p = 0.05?
  4. Write out the null hypothesis and the alternate hypothesis.
  5. What is your decision regarding the null hypothesis?
  6. Can we conclude any of the treatment means differ?
Math   Statistics-And-Probability   
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Homework Answers

Answer #1

(a)

Number of treatments = k = 3 + 1 = 4

(b)

Total sample size = N = 456 + 1 = 457

(c)

For = 0.05,& Degrees of Freedom of numerator = 3 & Degrees of Freedom of denominator = 453, from Table:

Critical Value of F = 2.625

(d)

H0: Null Hypothesis:

HA: Alternative Hypothesis: (At least one mean is different from other 3 means)

(e) Since calculated value of F = 21.73is greater than critical value of F = 2.625, the difference is significant. Reject null hypothesis.

(f)

We can conclude that any of the treatment means differ.

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