Question

Given the results of the Tukey's test presented in table 1, what can the researcher conclude?...

Given the results of the Tukey's test presented in table 1, what can the researcher conclude?

Table 1. Tukey's Test Results

Tukey’s Test Statistic

Differences between the averages

T0.05 = 23.05

Average 1 – Average 2 = 12.05

Average 1 – Average 3 = 25.18

Average 2 – Average 3 = -2.41

Homework Answers

Answer #1

Based on the above, we would compare the difference in means with the test statistic. If the test statistic > difference between the averages, then the differences are not statistically significant,

For the first pair Average 1 – Average 2 = 12.05 < T0.05 = 23.05. Hence we can conclude the difference between the means for 1 and 2 is not statistically significant.

For the first pair Average 1 – Average 3 = 25.18 > T0.05 = 23.05. Hence we can conclude the difference between the means for 1 and 3 are statistically significant.

For the first pair Average 2 – Average 3 = -2.41 < T0.05 = 23.05. Hence we can conclude the difference between the means for 2 and 3 are not statistically significant.

Let me know in comments if anything is not clear. Will reply ASAP. Please do upvote if satisfied.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Use a t-distribution and the given matched pair sample results to complete the test of the...
Use a t-distribution and the given matched pair sample results to complete the test of the given hypotheses. Assume the results come from random samples, and if the sample sizes are small, assume the underlying distribution of the differences is relatively normal. Assume that differences are computed using d=x1-x2. Test H0 : μd=0 vs Ha : μd>0 using the paired data in the following table: Situation 1 120 156 145 175 153 148 180 135 168 157 Situation 2 120...
Given the following contingency table, conduct a test for independence at the 1% significance level. (You...
Given the following contingency table, conduct a test for independence at the 1% significance level. (You may find it useful to reference the appropriate table: chi-square table or F table) Variable A Variable B 1 2 1 38 43 2 32 62 a. Choose the null and alternative hypotheses. H0: The two variables are independent.; HA: The two variables are dependent. H0: The two variables are dependent.; HA: The two variables are independent. b. Calculate the value of the test...
A researcher conducts a 2 way ANOVA test with interaction and provides the following ANOVA table....
A researcher conducts a 2 way ANOVA test with interaction and provides the following ANOVA table. Find the missing values in the ANOVA table. Source SS Df MS F p-value F crit Sample 700.21 2 .014 Columns 12,199.15 1 5.02E-09 Interaction 56.34 2 0.62 Within 680.38 12 Total 13,636.08 17 At the 5% significance level, can you conclude that there is an interaction effect? At the 5% significance level, can you conclude that the column means differ? At the 5%...
1. A researcher wants to test whether color can influence recall of words in a list....
1. A researcher wants to test whether color can influence recall of words in a list. To test this, the researcher displays 20 words on a computer screen. Ten words are in color, and 10 words are in black. All words are presented on a white background. Participants are given 1 minute to view the list, and then the list is taken away and participants are allowed 1 additional minute to write down as many words as they can recall....
Conduct a hypotheses test using the given information. A researcher wishes to test the claim that...
Conduct a hypotheses test using the given information. A researcher wishes to test the claim that the average cost of tuition and fees at a four-year public college is greater than $5700. She selects a random sample of 36 four-year public colleges and finds the mean to be $5950. The population standard deviation is $659. Is there evidence to support the claim at a significance level of 0.05? 1. Set up appropriate hypotheses. 2. Compute the test statistic. 3. Compute...
Given the following contingency table, conduct a test for independence at the 1% significance level. (You...
Given the following contingency table, conduct a test for independence at the 1% significance level. (You may find it useful to reference the appropriate table: chi-square table or F table) Variable A Variable B 1 2 1 33 50 2 45 50 b. Calculate the value of the test statistic. (Round intermediate calculations to at least 4 decimal places and final answer to 3 decimal places.)
A researcher conducts a two-way ANOVA test with interaction and provides the following ANOVA table. a....
A researcher conducts a two-way ANOVA test with interaction and provides the following ANOVA table. a. Find the missing values in the ANOVA table. (Round your answers to 2 decimal places.)   ANOVA   Source of Variation SS df        MS       F p-value F crit   Sample 766.98   2 MSB =    Ffactor B =    0.0109   3.885    Columns 12,122.69   1 MSA =    Ffactor A =    0 4.747    Interaction 57.60   2 MSAB =    FInteraction =    0.6148 3.885    Within 682.14 12 MSE =       Total 13,629.41 17 b....
Question 1. The following table summarizes the results of the test on the three branches. SUMMARY...
Question 1. The following table summarizes the results of the test on the three branches. SUMMARY Groups Count Sum Average Variance Branch 1 5 266 53.2 177.2 Branch 2 5 340 68 147.5 Branch 3 5 389 77.8 178.7 ANOVA Source of Variation SS df MS F P-value F crit Between Groups 1533.73 2.00 766.87 4.57 0.03 3.89 Within Groups 2013.60 12.00 167.80 Total 3547.33 14.00 a) Interpret the results of the ANOVA. b) Which branch deserves the reward for...
A multinomial experiment produced the following results (Use Table 3):   Category 1 2 3 4 5...
A multinomial experiment produced the following results (Use Table 3):   Category 1 2 3 4 5   Frequency 62 58 65 70 70    a. Choose the appropriate alternative hypothesis to test if the population proportions differ. All population proportions differ from 0.20. Not all population proportions are equal to 0.20. b. Calculate the value of the test statistic. (Round intermediate calculations to 4 decimal places and your final answer to 2 decimal places.)    χ2df    c. Specify the decision rule...
A one-way analysis of variance experiment produced the following ANOVA table. (You may find it useful...
A one-way analysis of variance experiment produced the following ANOVA table. (You may find it useful to reference the q table). SUMMARY Groups Count Average Column 1 6 0.71 Column 2 6 1.43 Column 3 6 2.15   Source of Variation SS df MS F p-value Between Groups 10.85 2 5.43 20.88 0.0000 Within Groups 3.86 15 0.26 Total 14.71 17 SUMMARY Groups Count Average Column 1 6 0.71 Column 2 6 1.43 Column 3 6 2.15 ANOVA Source of Variation...