Part a
The parameter of interest is given as population average permissible exposure limit.
Notation: µ = 1 ppm
Part b
The null and alternative hypotheses are given as below:
Null hypothesis: H0: The permissible exposure limit is 1 ppm.
Alternative hypothesis: Ha: The permissible exposure limit is greater than 1 ppm.
H0: µ = 1 versus Ha: µ > 1
This is an upper tailed test.
Part c
The test statistic formula is given as below:
t = (Xbar - µ)/[S/sqrt(n)]
We are given
Xbar = 2.1
S = 4.1
n = 36
df = n – 1 = 35
t = (2.1 – 1)/[4.1/sqrt(36)]
t = 1.6098
Test statistic = t = 1.6098
Part d
We have t = 1.6098
df = 35
So, p-value by using t-table is given as below:
P-value = 0.0582
Part e
We are given
P-value = 0.0582
α = 0.01
P-value > α = 0.01
So, we do not reject the null hypothesis
There is insufficient evidence to conclude that permissible exposure limit has been exceeded.
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