The lifetime of a certain battery follows a normal distribution with a mean 276 minutes and standard deviation 25 minutes. We took a random sample of 100 of these batteries. What is the probability that the sample mean of the lifetime will be less than 270 minutes?
Solution :
Given that ,
mean = = 276
standard deviation = = 25
n = 100
= 276
= / n = 25 / 100 = 2.5
P( < 270 ) = P(( - ) / < ( 270 - 276 ) / 2.5 )
= P( z < -2.4 )
Using z table
= 0.0082
Probability = 0.0082
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