Question

Determine mu Subscript x overbar and sigma Subscript x overbar from the given parameters of the population and sample size. muequals73​, sigmaequals17​, nequals23 mu Subscript x overbarequals nothing sigma Subscript x overbarequals nothing ​(Round to three decimal places as​ needed.)

Answer 1

Solution :

Given that,

mean = = 73

standard deviation = = 17

n = 23

The sampling distribution of mean is ,

= 73

The sampling distribution of standard deviation is ,  

= / n = 17 / 23 = 3.545