If
X overbar =68,
S=6,
and
n=81,
and assuming that the population is normally distributed, construct a
95%
confidence interval estimate of the population mean,
μ.
Solution :
Given that,
Point estimate = sample mean = = 68
sample standard deviation = s = 6
sample size = n = 81
Degrees of freedom = df = n - 1 = 81 - 1 = 80
At 95% confidence level the t is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
t /2,df = t0.025,80 = 1.990
Margin of error = E = t/2,df * (s /n)
= 1.990 * (6 / 81)
= 1.33
The 95% confidence interval estimate of the population mean is,
- E < < + E
68 - 1.33 < < 68 + 1.33
66.67 < < 69.33
(66.67 , 69.33)
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