ANOVA summary table. A partially completed ANOVA tale for a competely randomized design is shown here.
Source |
df |
SS |
MS |
F |
Treatments Error |
4 |
24.7 |
||
Total |
34 |
62.4 |
(a) Complete the ANOVA table.
(b) How many treatments are involved in the experiment?
(c) Do the data provide sufficient evidence to indicate a difference among the treatment means? Test using α = .10.
(A) df(error) = df(total)-df(treatments) = 34-4 = 30
ss(error) = ss(total)-ss(treatments) = 62.4 - 24.7 = 37.7
MS(error) = ss(error)/df(error) = 37.7/30 = 1.26
MS(treatment) = ss(treatment)/df(treatment) = 24.7/4 = 6.18
F = MS(treatment)/MS(error)= 6.18/1.26 = 4.90
(B) Number of treatments = df(treatments) + 1
= 4 + 1
= 5
(C) Using F distribution to find the p value corresponding F statistics, we get
p value = 0.0037
p value is less than 0.10 level of significance, rejecting the null hypothesis.
We can conclude that there is sufficient evidence to indicate a difference among the treatment means
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