X has a normal distribution with the given mean and a standard deviation. Find the indicated probability. (Round your answer to four decimal places.) μ = 108, σ = 15, find P(111 ≤ X ≤ 129)
Solution :
Given that,
mean =
= 108
standard deviation =
= 15
P (111
x
129 )
P ( 111 - 108 / 15 )
( x -
/
)
(129 - 108 / 15 )
P ( 3 / 15
z
21 / 15 )
P ( 0.2
z
1.4 )
P ( z
1.4 ) - P ( z
0.2 )
Using z table
= 0.9192 - 0.5793
= 0.3399
Probability = 0.3399
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