X has a normal distribution with the given mean and a standard deviation. Find the indicated probability. (Round your answer to four decimal places.) μ = 108, σ = 15, find P(111 ≤ X ≤ 129)
Solution :
Given that,
mean = = 108
standard deviation = = 15
P (111 x 129 )
P ( 111 - 108 / 15 ) ( x - / ) (129 - 108 / 15 )
P ( 3 / 15 z 21 / 15 )
P ( 0.2 z 1.4 )
P ( z 1.4 ) - P ( z 0.2 )
Using z table
= 0.9192 - 0.5793
= 0.3399
Probability = 0.3399
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