Question

On February 11, 2020 the World Health Organization announced an official name for the disease that is causing the 2019 novel coronavirus outbreak. The new name of this disease is coronavirus disease 2019, abbreviated as COVID-19. In COVID-19, ‘CO’ stands for ‘corona,’ ‘VI’ for ‘virus,’ and ‘D’ for disease.

Suppose that we wanted to take a sample of the citizens of a particular city to determine the percentage of people who have, or are carrying, COVID-19. Suppose that the level of precision we require is such that a 95% confidence interval is no wider than 5%. How large a sample is needed?

Note: The width of the confidence interval is twice the margin of error

A)1537

B)1536

C)384

D)358

Answer 1

given data are:-

margin of error (E)= 0.05 /2 = 0.025

[as we know that width of confidence interval is twice of margin of error]

sample proportion () = 0.5 [ as we do not have any prior estimate]

z critical value for 95% confidence level, both tailed test be:-

the needed sample size be:-

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