If n = 81, find the critical values X2/L and X 2/R for a confidence level of 99%.
Solution :
Given that,
n = 81
At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
1 - / 2 = 1 - 0.005 = 0.995
df = n - 1 = 81 - 1 = 80
Using 2 table,
2L = 2 / 2 = 20.005 = 116.321
2R = 21 - / 2 = 20.995 = 51.172
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