Question

10.5

10

10

10

11

10

12.5

8

15

0

12.75

11

20

15

10

10

15

10

12

13.5

15

10

10

11.5

14.75

15

18

10.5

11

12

14

14.5

15

13

11

8.5

10

16

11

10

10

10

10

10.5

11

8

12

12

9

11.5

How unlikely is your sample to occur in a given population

Create a hypothesis test

Null is 11

Alternative is not equal to 11

Answer 1

n = 50

sample mean =

satndard deviation = S = 3.0343

Null and alternative hypothesis is

H0 : u = 11

H1 : u ≠ 11

Here population standard deviation is not known so we use t-test statistic.

Test statistic is

Degrees of freedom = n - 1 = 50-1=49

P-value = 0.1548 ( using t table)

P-value , Failed to Reject H0

conclusion : Failed to Reject H0 . At 5% level of significance we say that population mean is equal to 11