Question

1. In 2001 it was estimated that 23% of college students either already had or was planning to get a tattoo within the next month. What is the probability that in a summer statistics class of 53 students, between 5 and 15 students either have or plan to get a tattoo within the next month?

ANSWER QUESTIONS A-G/DRAW AND LABEL NORMAL CURVE

(A) label the x-axis with a complete description in the context of the setting on the provided Normal curve.

(B) label the value of the mean

(C) label the value of the standard deviation in relation to the inflection points of the curve

(D) give the value of the requested probability, and show the shaded region

(E) show the location of x- value(s) on x-axis.

(F) Indicate the distance, z.

(G) Give your answer in a sentence

Answer #1

The value of the mean number of students out of 53 who either had or plan to get a tattoo is

= 23% of 53

= 1219/100 = 12.19

The variance of the number of students out of 53 who either had or plan to get a tattoo is

= 53 * 0.23 * (1-0.23)

= 9.386

The probability that between 5 to 15 students out of 53 either had or plan to get a tattoo is

The labelled normal curve representing this probability is

Answer - There is a probability of 0.8109 that out of 53 students, between 5 to 15 will either have a tattoo or will plan top get one.

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