Question

Suppose A and B are two events with P(A)=.36, P(B)=.48, and P(A or B)=.6 a. Find...

Suppose A and B are two events with P(A)=.36, P(B)=.48, and P(A or B)=.6

a. Find P(A n B)

b. Find P(A l B)

c. are A and B independent events? explain why using probability

. Are A and B disjoint events? explain why or why not using probability

Math   Statistics-And-Probability   
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Homework Answers

Answer #1

a) P(A B) = P(A) + P(B) - P(A U B)

                    = 0.36 + 0.48 - 0.6

                    = 0.24

b) P(A | B) = P(A B)/P(B)

                  = 0.24/0.48 = 0.5

c) P(A) * P(B) = 0.36 * 0.48 = 0.1728

Since P(A B) P(A) * P(B), so the events A and B are not independent.

Since P(A B) 0, so events A and B are not disjoint.

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