Below is a regression using X = average price, Y = units sold, n = 20 stores. |
R2 | 0.200 |
Std. Error | 26.128 |
n | 20 |
ANOVA table | |||||
Source | SS | df | MS | F | p-value |
Regression | 3,080.89 | 1 | 3,080.89 | 4.51 | .0478 |
Residual | 12,288.31 | 18 | 682.68 | ||
Total | 15,369.20 | 19 | |||
Regression output | confidence interval | |||||
variables | coefficients | std. error | t (df = 18) | p-value | 95% lower | 95% upper |
Intercept | 614.9300 | 51.2343 | 12.002 | .0000 | 507.2908 | 722.5692 |
Slope | −109.1120 | 51.3623 | −2.124 | .0478 | −217.0202 | −1.2038 |
(a) | Write the fitted regression equation. (Round your answer to 3 decimal places. Negative values should NOT be indicated by a minus sign.) |
YˆY^ = − X |
(b) |
Write the formula for each t statistic and verify the t statistics shown below. (Round your answer to 3 decimal places. Negative values should be indicated by a minus sign.) |
t | |
Intercept | |
Slope | |
(c) |
State the degrees of freedom for the t tests and find the two-tail critical value for t by using Appendix D. (Round t.025 value to 3 decimal places.) |
df | |
t.025 | ± |
(d) |
Use Excel's function =T.DIST.2T(t, d.f.) to verify the p-value shown for each t statistic (slope, intercept). (Round your answer to 4 decimal places.) |
p-value | ||
Intercept | ||
Slope | ||
(e-1) | Calculate t2 for slope and show that F = t2. (Round your answer to 3 decimal places.) |
F = t2 |
(e-2) | Calculate R2. (Round your answer to 3 decimal places.) |
R2 |
(e-3) |
The percentage of variation in units sold that can be explained by average price is %. (Round your answer to 3 decimal places.) |
(f) | Choose the option that best describes the fit of this regression. | ||||
|
Answer:
Below is a regression using
x=average price
y=units sold
n=20 stores
a) we know that the regression equation is given by y=a+bx
from above analysis
y=614.93 -109.112(average price)
b) we use t test with n-2 df
intercept t=b1-0 / sb1 = 614.93 / 51.23623 = 12.002
slop t = b0-0 / sb0 = -109.112 / 51.23626= -2.124
c) degrees of freedom = n-2
20-2=18
two tailed critical value =2.101 from t table
d) Use Excel's function =T.DIST.2T(t, d.f.)
T DIST(2.124 ,18,2) = 0.0477 (SLOPE)
T DIST (12.002,18,2) = 0.000(INTERCEPT )
e)
e - 1: F = t2 = (-2.124)2 = 4.511
e - 2: R2 = 0.200
e - 3: The percentage of variation in units sold that can be explained by average price is 20%
f: This model has a poor fit.
Thank you!
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