The percentage of students who attend a local school in any given school week is as follows:
Monday | Tuesday | Wednesday | Thursday | Friday |
95% | 96% | 98% | 97% | 95% |
In one given school week, the number of students (data) who attended school out of a student population of 500 was:
Monday | Tuesday | Wednesday | Thursday | Friday |
450 | 470 | 485 | 480 | 470 |
a=0.05
Perform a goodness of fit hypothesis test to determine if the numbers fit the percentages given.
Monday | Tuesday | Wednesday | Thursday | Friday | |
Expected | 95 | 96 | 98 | 97 | 95 |
Observed | 90 | 94 | 97 | 96 | 94 |
Null hypothesis: The numbers fit the percentages given
Alternate hypothesis: The numbers do not fit the percentages given.
Degrees of freedom = k-1 = 5-1 =4
Test statistic is
we use Chi-square distribution calculator to find P(Χ2 > 0.3359) = 0.99
AS p-value is greater than 0.05. we fail to reject null hypothesis.
we can conclude that the numbers fit the percentages given.
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