Problem 3-17 (Algorithmic) Airline passengers arrive randomly and independently at the passenger screening facility at a major international airport. The mean arrival rate is 8 passengers per minute. A)
What is the probability of no arrivals in a 1-minute period? If required, round your answer to six decimal places.
B)What is the probability of 3 or fewer arrivals in a 1-minute period? If required, round your answer to six decimal places.
C)What is the probability of no arrivals in a 18-second period? If required, round your answer to four decimal places.
D)What is the probability of at least 1 arrival in a 18-second period? If required, round your answer to four decimal places.
X ~ Poisson ()
Poisson probability distribution is
P( X = x) = e-X / X!
a)
= 8 per min
P( X = 0) = e-8
= 0.000335
b)
P( X <= 3) = P( X = 0) +P( X = 1) +P( X = 2) +P( X = 3)
= e-8 + e-8 * 8 + e-8 * 82 / 2! + e-8 * 83 / 3!
= 0.042380
c)
For 18 second period,
= 8 * 18 / 60 = 2.4
P(X = 0) = e-2.4
= 0.0907
d)
P( X >= 1) = 1 - P( X = 0)
= 1 - 0.090718
= 0.9093
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