for normal distribution z score =(X-μ)/σ |
a)
probability =P(X>65000)=P(Z>(65000-53901)/15000)=P(Z>0.74)=1-P(Z<0.74)=1-0.7704=0.2296 |
b)
probability =P(X>65000)=P(Z>(65000-51541)/11000)=P(Z>1.22)=1-P(Z<1.22)=1-0.8888=0.1112 |
c)
probability =P(X<40000)=(Z<(40000-51541)/11000)=P(Z<-1.05)=0.1469 |
d)
for 99th percentile critical value of z= | 2.33 |
therefore corresponding value=mean+z*std deviation=53901+2.33*11000 = | 77171.00 |
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