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The citizens of Brownsville have a monthly income that is normally distributed with an average of...

The citizens of Brownsville have a monthly income that is normally distributed with an average of $3000 and with standard deviation of $500. Based on this, one can find the range of income for the middle 95% of its citizens (income that mark separate the bottom and the top 2.5% of the income distribution). What is the income of that separates the poorest 2.5% from the rest? (round to whole number).

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