A statistician wants to estimate the mean loss suffered by Delta pilots in the labor negotiations to lower Delta salaries to within $2500 with 95% confidence. From a first small survey, the standard deviation of the loss is estimated at $10,000. What size sample should the statistician select?
Solution
standard deviation =s = =10000
Margin of error = E = 2500
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96
sample size = n = [Z/2* / E] 2
n = ( 1.96* 10000/ 2500)2
n =61.466
Sample size = n =61
None of the above
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