.Let X be a random variable that takes the value 0 with probability 1/2, and takes the value 1 with probability 1/2; let Y be a random variable, independent of X, that takes the value 1 with probability 1/2, and takes the value −1 with probability 1/2; and let Z = XY . Show that Cov(X, Z) = 0. Show that X and Z are dependent
X = 1 with p =1/2
0 with p = 1/2
Y = 1 with p = 1/2
-1 with p = 1/2
Z = XY
X/Y | 1 | -1 |
0 | 0.25 | 0.25 |
1 | 0.25 | 0.25 |
Z | p |
0 | 0.5 |
1 | 0.25 |
-1 | 0.25 |
Cov(X,Z) = E(XZ) - E(X)E(Z)
joint distribution of X and Z
X/Z | 0 | 1 | -1 |
0 | 0.5 | 0 | 0 |
1 | 0 | 0.25 | 0.25 |
hence
Cov(X,Z) = 0
X/Z | 0 | 1 | -1 | |
0 | 0.5 | 0 | 0 | 0.5 |
1 | 0 | 0.25 | 0.25 | 0.5 |
0.5 | 0.25 | 0.25 | 1 |
P(X = 0, Z =0) = 0.5
P(X = 0) = 0.5 and P(Z = 0) = 0.5
P(X = 0) * P(Z =0) = 0.25
since P(X = 0, Z =0) P(X = 0) * P(Z =0)
X and Z are dependent
Please rate
Get Answers For Free
Most questions answered within 1 hours.