Women have head circumferences that are normally distributed with a mean given by u= 23.76in, and a standard deviation given by o= 1.1in.
a. If a hat company produces women's hats so that they fit head circumferences between 23.1 in. and 24.1 in., what is the probability that a randomly selected woman will be able to fit into one of these hats? The probability is . 4165. (Round to four decimal places as needed.)
b. If the company wants to produce hats to fit all women except for those with the smallest 2.5% and the largest 2.5% head circumferences, what head circumferences should be accommodated?
The minimum head circumference accommodated should be ___in. (Round to two decimal places as needed.)
The maximum head circumference accommodated should be nothing ___in. (Round to two decimal places as needed.)
solution:-
given that mean µ = 23.76 , standard deviation σ = 1.1
a.P(23.1 < x < 24.1)
=> P((23.1-23.76)/1.1 < z < (24.1-23.76)/1.1)
=> P(-0.6 < z < 0.31)
=> P(z < 0.31) - P(z < -0.6)
=> 0.6217 - 0.2743
=> 0.3474
b. the probability is the are between the 0.025 is z = -1.96 and z
= 1.96 from standard normal distribution table
from that information
formula x = z*σ + µ
=> minimum = -1.96*1.1+23.76 = 21.60
=> maximum = 1.96*1.1+23.76 = 25.92
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