Question

Let A and B be mutually exclusive events with P(A) = 0.38 and P(B) = 0.48....

Let A and B be mutually exclusive events with P(A) = 0.38 and P(B) = 0.48.

a. Calculate P(A ∩ B). (Round your answer to 2 decimal places.)


b. Calculate P(A U B). (Round your answer to 2 decimal places.)


c. Calculate P(A | B).

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Homework Answers

Answer #1

Let A and B be mutually exclusive events with P(A) = 0.38 and P(B) = 0.48.

a. Calculate P(A ∩ B). (Round your answer to 2 decimal places.)

Since the events are mutually exclusive, P ( A ∩ B ) = 0

(or the probability of A and B happening together is = 0)

b. Calculate P(A U B). (Round your answer to 2 decimal places.)

P(A U B) = 0.38+0.48

=0.86

c. Calculate P(A | B).

since the Two are mutually exclusive events, both cannot occur at the same time. Therefore

P(A | B) = 0.

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