For the following questions, define each of the random variables
you use.
The life of the batteries produced by a manufacturer is distributed
according to a normal law with an average duration of 110 hours and
a standard deviation of 10 hours.
a) What proportion of the batteries produced will last more than
125 hours.
b) The warranty accompanying the batteries states that if a battery
lasts less than X hours the manufacturer agrees to replace
it. What should be the value of X if the manufacturer does
not want to replace more than 5% of the batteries sold.
Solution :
Given that ,
mean = = 110
standard deviation = = 10
(a)
P(x > 125) = 1 - P(x < 125)
= 1 - P((x - ) / < (125 - 110) / 10)
= 1 - P(z < 1.5)
= 1 - 0.9332
= 0.0668
P(x > 125) = 0.0668
Proportion = 0.0668
(b)
P(Z > z) = 5%
1 - P(Z < z) = 0.05
P(Z < z) = 1 - 0.05 = 0.95
P(Z < 1.645) = 0.95
z = 1.645
Using z-score formula,
x = z * +
x = 1.645 * 10 + 110 = 126.45
X = 125.45
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