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A consumer affairs investigator records the repair cost for 44 randomly selected TVs. A sample mean...

A consumer affairs investigator records the repair cost for 44 randomly selected TVs. A sample mean of $54.41 and standard deviation of $28.89 are subsequently computed. Determine the 90% confidence interval for the mean repair cost for the TVs. Assume the population is approximately normal.

Step 1 of 2:

Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.

Step 2 of 2:

Construct the 90% confidence interval. Round your answer to two decimal places.

Math   Statistics-And-Probability   
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