Question

Claim: Most adults would erase all of their personal
information

online if they could. A software firm survey of 677 randomly
selected

adults showed that 56% of them would erase all of their
personal

information online if they could. Find the value of the test

statistic.

The value of the test statistic is

nothing.

(Round to two decimal places as needed.)

Claim: The mean pulse rate (in beats per minute) of
adult males is

equal to 69 bpm. For a random sample of 149 adult males, the
mean

pulse rate is 68.7 bpm and the standard deviation is 10.6 bpm.
Find

the value of the test statistic.

The value of the test statistic is

nothing.

(Round to two decimal places as needed.)

please help

Answer #1

1)

Ho : p = 0.5

H1 : p > 0.5

Sample Size, n = 677

Sample Proportion , p̂ = 0.5600

Standard Error , SE = √( p(1-p)/n ) =
0.0192

Z Test Statistic = ( p̂-p)/SE = ( 0.5600
- 0.5 ) / 0.0192
**= 3.12 (answer)**

**---------------**

Standard Error , SE = s/√n = 10.6000 / √
149 =
0.8684**
t-test statistic=** (x̅ - µ )/SE = (
68.700 - 69 ) /
0.8684 =

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