Question

​Claim: Most adults would erase all of their personal information
online if they could. A software firm survey of 677 randomly selected
adults showed that 56​% of them would erase all of their personal
information online if they could. Find the value of the test
statistic.
The value of the test statistic is
nothing.
​(Round to two decimal places as​ needed.)

​Claim: The mean pulse rate​ (in beats per​ minute) of adult males is
equal to 69 bpm. For a random sample of 149 adult​ males, the mean
pulse rate is 68.7 bpm and the standard deviation is 10.6 bpm. Find
the value of the test statistic.
The value of the test statistic is
nothing.
​(Round to two decimal places as​ needed.)
please help

Answer 1

1)

Ho :   p =    0.5
H1 :   p >   0.5
Sample Size,   n =    677
      
Sample Proportion ,    p̂ =    0.5600

Standard Error ,    SE = √( p(1-p)/n ) =    0.0192                  
Z Test Statistic = ( p̂-p)/SE = (   0.5600   -   0.5   ) /   0.0192 =   3.12 (answer)

---------------

Standard Error , SE = s/√n =   10.6000   / √    149   =   0.8684      
t-test statistic= (x̅ - µ )/SE = (   68.700   -   69   ) /    0.8684   =   -0.35