Question

Given the data in Table A, develop a multivariate regression analysis of the relationship between Product...

Given the data in Table A, develop a multivariate regression analysis of the relationship between Product Demand and the other variables in the table (Average Customer Income, Number of Snow Days in Season, and the Average Gasoline Price).Do the results of your analysis confirm your expectations and do they make economic sense?

Regression Statistics
Multiple R 0.999999903
R Square 0.999999805
Adjusted R Square 0.999999799
Standard Error 1.031348397
Observations 100
ANOVA
df SS MS F Significance F
Regression 3 523836040.9 1.75E+08 1.64E+08 0
Residual 96 102.1132335 1.06368
Total 99 523836143
Coefficients Standard Error t Stat P-value Lower 95% Upper 95% Lower 95.0% Upper 95.0%
Intercept 35001.37051 0.998051161 35069.72 0 34999.38939 35003.35 34999.38939 35003.35
Average Customer Income 0.157489612 7.10596E-06 22163.02 0 0.157475507 0.157504 0.157475507 0.157504
Number of Snow Days In Season 23.64406609 0.007643789 3093.239 9.5E-242 23.62889329 23.65924 23.62889329 23.65924
Average Gasoline Price ($/gallon) -3.866980648 0.294996586 -13.1086 4.12E-23 -4.452544243 -3.28142 -4.452544243 -3.28142

Homework Answers

Answer #1

we know that multivariate equation for 3 independent variables is given as

y = a + bx + cy + dz

where a is intercept, b is slope coefficient for x, c is slope coefficient for y and d is slope coefficient for z

x is average customer income, y is number of snow days in season and z is average gasoline price

setting the value from the data table

we can write

y = 35001.3705 + 0.1574(Average customer income)+23.6441(number of snow days in season)-3.8670(average gasoline price)

(each coefficient value is rounded to 4 decimals)

Yes, it confirms out expectations because equation is showing logical data for each variable. For example, product is required more in snow days, so the coefficient of snow day is very high. Each one of the variables are significant.

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