Question

For a data set of the pulse rates for a sample of adult​ females, the lowest pulse rate is 3838 beats per​ minute, the mean of the listed pulse rates is x overbarxequals=72.072.0 beats per​ minute, and their standard deviation is sequals=20.220.2 beats per minute. a. What is the difference between the pulse rate of 3838 beats per minute and the mean pulse rate of the​ females? b. How many standard deviations is that​ [the difference found in part​ (a)]? c. Convert the pulse rate of 3838 beats per minutes to a z score. d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly​ high, is the pulse rate of 3838 beats per minute​ significant?

Answer 1

it is given that

beats per minute

beats per minute

(A) Difference = |given pulse rate - mean pulse rate|

given pulse rate is 38 and mean pulse rate is 72

so, difference = |38-72| = 34

(B) We have to find the number of standard deviation for the difference

So, number of standard deviation = (difference)/(standard deviation) = (34/20.2) = 1.68s

So, difference is 1.68 times the standard deviation

(C) Formula for z score =

where x = 38, x(bar) = 72 and s = 20.2

we get

z = (38-72)/20.2 = -34/20.2 = -1.68

(D) No, pulse is not significant because it fall within the range of -2 and +2 z score. Calculated z score value of -1.68 is between -2 and +2. So, it is not significant value.