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According to a survey of 25000 households, 45% of the people watching a special event on...

According to a survey of 25000 households, 45% of the people watching a special event on tv enjoyed the commercials more than the event itself. Complete parts a through e below based on a random sample of nine people who watched the special event.

a) what is the probability that exactly 3 people enjoyed the commercials more than the event?

B) what is the probability that less that 4 people enjoyed the commercials more than the event?

c) what is the probability that exactly 5 or 6 people enjoyed the commercials more than the event?

D)what is the Mean and standard deviations?

e)histogram

Math   Statistics-And-Probability   
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Answer #1

Let X denotes the number of people enjoyed the commercials more than the event in a random sample of nine people who watched the special event.

X ~ Binomial (n = 9, p = 0.45)

The probability mass function of X is

a) The probability that exactly 3 people enjoyed the commercials more than the event

b) The probability that less that 4 people enjoyed the commercials more than the event

c) The probability that exactly 5 or 6 people enjoyed the commercials more than the event

d)Mean = E(X) = 9*0.45 = 4.05

and Var(X) = 9*0.45*(1-0.45) = 2.2275

and standard deviation of X =

e)

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