According to a flight statistics website, in 2009, a certain airline had the highest percentage of on-time flights in the airlines industry, which was 81.3%. Assume this percentage still holds true for that airline. Determine the probability that, of the next 30 flights from this airline, less than 23 flights will arrive on time
Using Normal approximation to Binomial
Mean = n * P = 30 * 0.813 = 24.39
Standard deviation =
P(X < 23 )
Using continuity correction
P ( X < 23 ) = P ( X < 23 - 0.5 ) = P ( X < 22.5 )
P ( X < 22.5 )
Standardizing the value
Z = ( 22.5 - 24.39 ) / 2.1356
Z = -0.88
P ( X < 22.5 ) = P ( Z < -0.88 )
P ( X < 22.5 ) = 0.1894
P ( X < 30 ) = 0.1894
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