Question

A simple random sample of 48 adults is obtained from a normally distributed population, and each person's red blood cell count (in cells per microliter) is measured. The sample mean is

5.29 and the sample standard deviation is 0.53. Use a 0.01 significance level and the given calculator display to test the claim that the sample is from a population with a mean less than

5.4 which is a value often used for the upper limit of the range of normal values. What do the results suggest about the sample group?

**State the final conclusion that addresses the original
claim. Choose the correct answer below.**

A. Reject H0. There is not sufficient evidence to support the claim that the sample is from a population with a mean less than 5.4

B. Fail to reject H0. There is sufficient evidence to support the claim that the sample is from a population with a mean less than 5.4

C. Reject H0. There is sufficient evidence to support the claim that the sample is from a population with a mean less than 5.4

D. Fail to reject H0. There is not sufficient evidence to support the claim that the sample is from a population with a mean less than 5.4

**What do the results suggest about the sample
group?**

A. There is not enough evidence to conclude that the sample is from a population with a mean less than 5.4, so it is possible that the population has counts that are too high.

B. There is enough evidence to conclude that the sample is from a population with a mean less than 5.4, so it is possible that the population has counts that are too high.

C. There is not enough evidence to conclude that the sample is from a population with a mean less than 5.4, so it is unlikely that the population has counts that are too high.

D. There is enough evidence to conclude that the sample is from a population with a mean less than 5.4, so it is unlikely that the population has counts that are too high.

Answer #1

Below are the null and alternative Hypothesis,

Null Hypothesis, H0: μ = 5.4

Alternative Hypothesis, Ha: μ < 5.4

Test statistic,

t = (xbar - mu)/(s/sqrt(n))

t = (5.29 - 5.4)/(0.53/sqrt(48))

t = -1.438

P-value Approach

P-value = 0.0785

As P-value >= 0.01, fail to reject null hypothesis.

D. Fail to reject H0. There is not sufficient evidence to support
the claim that the sample is from a population with a mean less
than 5.4

A. There is not enough evidence to conclude that the sample is from
a population with a mean less than 5.4, so it is possible that the
population has counts that are too high.

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