a)
x | P(x) | xP(x) | x2P(x) |
35 | 1/38 | 0.921 | 32.237 |
-1 | 37/38 | -0.974 | 0.974 |
total | -0.053 | 33.211 | |
E(x) =μ= | ΣxP(x) = | -0.0526 | |
E(x2) = | Σx2P(x) = | 33.2105 | |
Var(x)=σ2 = | E(x2)-(E(x))2= | 33.208 | |
std deviation= | σ= √σ2 = | 5.7626 |
from above :
E(X)=-0.0526
SD(X)=5.7626
b)
for 1000 bets; expected win=1000*-0.526=-52.63
and std deviation =5.7626*sqrt(1000)=182.23
hence from normal approximation ;
probability that you will be winning after 1000 bets =P(X>0)=P(Z>(0-(-52.63))/182.23)=P(Z>0.29)=~0.39
c)
for 100000 bets; expected win=100000*-0.526=-5263.16
and std deviation =5.7626*sqrt(1000)=1822.30
hence from normal approximation ;
probability that you will be winning after 100000 bets =P(X>0)=P(Z>(0-(-5263.16))/1822.3)=P(Z>2.89)=~0.002
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