The FDA requires to determine the average fat content in mgs of red meat imported from Brazil. 10 laboratories reported the following average fat content in mgs. Calculate the sample standard deviation to the nearest hundredths mgs.
Laboratory | Fat Content (mgs) X | X2 |
1 | 11.2 | |
2 | 10.1 | |
3 | 9.6 | |
4 | 8.4 | |
5 | 7.3 | |
6 | 6.9 | |
7 | 12.1 | |
8 | 10.8 | |
9 | 7.7 | |
10 | 9.8 |
Laboratory | Fat Content (mgs) X |
1 | 11.2 |
2 | 10.1 |
3 | 9.6 |
4 | 8.4 |
5 | 7.3 |
6 | 6.9 |
7 | 12.1 |
8 | 10.8 |
9 | 7.7 |
10 | 9.8 |
Mean Fat Content for all 10 samples, m = Sum of all fat contents / 10 = 93.9 / 10 = 9.39
Laboratory | Fat Content (mgs) X | (X - m)2 |
1 | 11.2 | 3.2761 |
2 | 10.1 | 0.5041 |
3 | 9.6 | 0.0441 |
4 | 8.4 | 0.9801 |
5 | 7.3 | 4.3681 |
6 | 6.9 | 6.2001 |
7 | 12.1 | 7.3441 |
8 | 10.8 | 1.9881 |
9 | 7.7 | 2.8561 |
10 | 9.8 | 0.1681 |
Now, (X - m)2 = 27.729
Sample standard deviation,
So, s =
s =
s = 1.7552
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