check each data set for outliers a. 46, 28, 32, 21, 25, 29, 34, 19 b. 82, 100, 97, 93, 89, 90, 65, 94, 101 c. 527, 1007, 489, 371, 175
a) Arrange the given data in ascending order
1 | 19 |
2 | 21 |
3 | 25 |
4 | 28 |
5 | 29 |
6 | 32 |
7 | 34 |
8 | 46 |
Q1 = (21 + 25)/2 = 23
Q3 = (32 + 34)/2 = 33
IQR = 33 - 23 = 10
Lower fence = Q1 - 1.5*IQR = 23 - 1.5*10 = 8
Lower fence = Q1 + 1.5*IQR = 23 + 1.5*10 = 38
For this data set 46 is an outlier
b)
1 | 65 |
2 | 82 |
3 | 89 |
4 | 90 |
5 | 93 |
6 | 94 |
7 | 97 |
8 | 100 |
9 | 101 |
Q1 = (82 + 89)/2 = 85.5
Q3 = (97 + 100)/2 = 98.5
IQR = 98.5 - 85.5 = 13
Lower fence = Q1 - 1.5*IQR = 85.5 - 1.5*13 = 66
Lower fence = Q1 + 1.5*IQR = 98.5 + 1.5*13 = 118
For this data set 65 is an outlier
c)
1 | 175 |
2 | 371 |
3 | 489 |
4 | 527 |
5 | 1007 |
Q1 = (175 + 371)/2 = 273
Q3 = (527 + 1007)/2 = 767
IQR = 767 - 273 = 494
Lower fence = Q1 - 1.5*IQR = 273 - 1.5*494 = -468
Lower fence = Q1 + 1.5*IQR = 767 + 1.5*494 = 1508
For this data set there is no outlier
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