A random sample of 10 children found that their average growth for the first year was 9.8 inches. Assume the variable is normally distributed and the sample standard deviation is 0.96 inch. Find the 95% confidence interval of the population mean for growth during the first year.
We have given that,
Sample mean =9.8
Sample standard deviation =0.96
Sample size =10
Level of significance=0.05
Degree of freedom =9
t critical value is (by using t table)=2.2622
Confidence interval formula is
=(9.11,10.47)
Lower confidence limit= 9.11
Upper confidence limit= 10.47
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