Question

The weights of steers in a herd are distributed normally. The variance is 90,000 and the mean steer weight is 1300lbs. Find the probability that the weight of a randomly selected steer is between 850 and 1656lbs. Round your answer to four decimal places.

Answer 1

given that variance = 90000

this implies standard deviation = sqrt(variance).......................sqrt means square root of variance

= sqrt(90000)

= 300

now, mean = 1300, standard deviation = 300

We have to find the probability that the weight of a randomly selected steer is between 850 and 1656lbs

using normalcdf(lower bound, upper bound, mean, standard deviation)

where mean = 1300, standard deviation = 300, lower bound = 850 and upper bound = 1656

this implies

= normalcdf(850,1656,1300,300)

= 0.8155