Question

Suppose you have a sample of size 33 with a mean of 39 and a population standard deviation of 14.5. What is the maximal margin of error associated with a 95% confidence interval for the true population mean? In your calculations, use z = 2. Give your answer as a decimal, to two places m = ounces

Answer 1

A margin of error is the error associated with calculations, or in statistics it is defined as the amount associated with sampling error. The larger the margin of error, the greater the chance of obtaining the true population parameter within the limits of the interval calculated.

The ME = Critical * (s or ) / Sqrt(n)

Where critical is the critical value (Z or t) at the given confidence level

s or = the sample or population standard deviation respectively, depending on what is available

n = the sample size.

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ME = Z critical * / Sqrt(n) = 2 * 14 / Sqrt(33) = 4.87 ounces

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