Question

I would like to know how to solve this problem using calculator TI 84.

A data set includes data from student evaluations of courses. The summary statistics are n=90, x̄=3.68, s=0.63. Use a 0.10 significance level to test the claim that the population of student course evaluations has a mean equal to 3.75. Assume that a simple random sample has been selected. Identify the null and alternative hypothesis, test statistics, P-value, and state the final conclusion that addresses the original claim.

Answer 1

Ans:

Press STAT and the right arrow twice to select TESTS.

To select the highlighted
1:Z-Test…

Enter sample statistics,assume s as sigma,as n is sufficiently large,so we can estimate population standard deviation from sample standard deviation.

Test statistic:

z=(3.68-3.75)/(0.63/sqrt(90))

z=-1.054

critical z values(two tailed)=+/-1.645

p-value=2*P(z<-1.054)=0.1459

As,p-value>0.1,we fail to reject the null hypothesis.

There is not sufficient evidence to reject the claim.