Question

How much should a healthy kitten weigh? Suppose that a healthy 10-week-old (domestic) kitten should weigh an average of μ = 26.3 ounces with a (95% of data) range from 14.8 to 37.8 ounces. Let x be a random variable that represents the weight (in ounces) of a healthy 10-week-old kitten. Assume that x has a distribution that is approximately normal. (a) The empirical rule (Section 7.1) indicates that for a symmetrical and bell-shaped distribution, approximately 95% of the data lies within two standard deviations of the mean. Therefore, a 95% range of data values extending from μ − 2σ to μ + 2σ is often used for "commonly occurring" data values. Note that the interval from μ − 2σ to μ + 2σ is 4σ in length. This leads to a "rule of thumb" for estimating the standard deviation from a 95% range of data values. Estimating the standard deviation For a symmetric, bell-shaped distribution, standard deviation ≈ range 4 ≈ high value − low value 4 where it is estimated that about 95% of the commonly occurring data values fall into this range.

Estimate the standard deviation of the x distribution. (Round your answer to two decimal places.) oz

(b) What is the probability that a healthy 10-week-old kitten will weigh less than 14 ounces? (Round your answer to four decimal places.)

(c) What is the probability that a healthy 10-week-old kitten will weigh more than 33 ounces? (Round your answer to four decimal places.)

(d) What is the probability that a healthy 10-week-old kitten will weigh between 14 and 33 ounces? (Round your answer to four decimal places.)

(e) A kitten whose weight is in the bottom 14% of the probability distribution of weights is called undernourished. What is the cutoff point for the weight of an undernourished kitten? (Round your answer to two decimal places.) oz

Answer 1

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Refer Z-table or Use excel formula "=NORM.S.DIST(1.04, TRUE)" to find the probability.

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Refer Z-table or Use excel formula "=NORM.S.DIST(-0.83, TRUE)" to find the probability.

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Refer Z-table or Use excel formula "=NORM.S.DIST(-0.83, TRUE)" & "=NORM.S.DIST(-4.14, TRUE)" to find the probability.

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Refer Z-table to find the Z-value to the left of the normal curve or Use excel formula "=NORM.S.INV(0.14)" to find the Z-value.