Question

A manufacturer claims that the mean weight of flour in its 32-ounce bags is its 32.1 ounces. A T-Test is performed to determine whether the mean weight is actually less than this. The mean weight for a random sample of 45 bags of flour was 30.7 ounces with a standard deviation of 2.5 ounces. Test the claim at the 5% significance level.

a) Check the assumptions:

b) Hypotheses (State in symbols and in words): Ho: Ha:

c) Test Statistic: ___________________

d) Sketch:e) P-Value: ___________________

f) Conclusion:

Answer #1

A manufacturer claims that the mean weight of flour in its
32-ounce bags is 32.1 ounces. A T-Test is performed to determine
whether the mean weight is actually less than this. The mean weight
for a random sample of 45 bags of flour was 30.7 ounces with a
standard deviation of 2.5 ounces. Test the claim at the 5%
significance level.
a) Check the assumptions:
b) Hypotheses (State in symbols and in words):
Ho:
Ha:
c) Test Statistic: d) Sketch:...

A 32 ounce can of a popular fruit drink claims to contain 20%
real fruit juice. Since this is a 32 ounce can, they are actually
claiming that the can contains 6.4 ounces of real fruit juice. The
consumer protection agency samples 46 such cans of this fruit
drink. Of these, the mean volume of fruit juice is 6.35 with
standard deviation of 0.21. Test the claim that the mean amount of
real fruit juice in all 32 ounce cans...

Real Fruit Juice: A 32 ounce can of a popular
fruit drink claims to contain 20% real fruit juice. Since
this is a 32 ounce can, they are actually claiming that the can
contains 6.4 ounces of real fruit juice. The consumer
protection agency samples 44 such cans of this fruit drink. Of
these, the mean volume of fruit juice is 6.32 with standard
deviation of 0.23. Test the claim that the mean amount of real
fruit juice in all...

Real Fruit Juice: A 32 ounce can of a popular fruit drink claims
to contain 20% real fruit juice. Since this is a 32 ounce can, they
are actually claiming that the can contains 6.4 ounces of real
fruit juice. The consumer protection agency samples 42 such cans of
this fruit drink. Of these, the mean volume of fruit juice is 6.34
with standard deviation of 0.21. Test the claim that the mean
amount of real fruit juice in all...

A famous food manufacturer claims that the mean weight of their
chocolate bars is 2.66 ounces with standard deviation 0.45 ounces.
A consumer watchdog group sampled 150 chocolate bars from this
company. The mean weight is 2.29 ounces. Set up a hypothesis test
at the significance level 0.10 Part 1: what is the H1 statement?
Part 2: what is the claim? Part 3: what is the p-value? Select one:
a. Part 1 H1 μ < 2.66 Part 2 H1 is...

A company claims that the mean net weight of the contents of its
brand T cereal boxes is at least 18 ounces. Suppose you want to
test whether or not the claim of the company is true. Explain
briefly how you would conduct this test using a large sample.
Assume that ? = 0.25 ounce.

A local chip manufacturer distributes chips in bags labeled as
150g. A group of consumers believe they are being cheated. They run
a test on 32 bags, measures their contents, and obtains a sample
mean of 145 grams with a standard deviation of 6 ounces. Use a 0.01
significance level to test the consumer's claim that the company is
cheating its customers.
Null Hypothesis:
Alternate Hypothesis:
P-value: Conclusion:
Interpretation:

Real Fruit Juice (Raw Data, Software
Required):
A 32 ounce can of a popular fruit drink claims to contain 20%
real fruit juice. Since this is a 32 ounce can, they are
actually claiming that the can contains 6.4 ounces of real
fruit juice. The consumer protection agency samples 30 such
cans of this fruit drink. The amount of real fruit juice in each
can is given in the table below. Test the claim that the mean
amount of real...

Real Fruit Juice (Raw Data, Software Required): A 32 ounce can
of a popular fruit drink claims to contain 20% real fruit juice.
Since this is a 32 ounce can, they are actually claiming that the
can contains 6.4 ounces of real fruit juice. The consumer
protection agency samples 30 such cans of this fruit drink. The
amount of real fruit juice in each can is given in the table below.
Test the claim that the mean amount of real...

Real Fruit Juice (Raw Data, Software
Required):
A 32 ounce can of a popular fruit drink claims to contain 20%
real fruit juice. Since this is a 32 ounce can, they are
actually claiming that the can contains 6.4ounces of real fruit
juice. The consumer protection agency samples 30 such cans of
this fruit drink. The amount of real fruit juice in each can is
given in the table below. Test the claim that the mean amount of
real fruit...

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