Construct a normal probability plot for the following sample of observations on coating thickness for low-viscosity paint.
0.82 | 0.87 | 0.90 | 1.03 | 1.08 | 1.13 | 1.29 | 1.33 |
1.46 | 1.50 | 1.58 | 1.62 | 1.66 | 1.72 | 1.76 | 1.85 |
Determine the z percentile associated with each sample observation. (Round your answers to two decimal places.)
Sample observation | 0.82 | 0.87 | 0.90 | 1.03 | 1.08 | 1.13 | 1.29 | 1.33 |
z percentile | ||||||||
Sample observation | 1.46 | 1.50 | 1.58 | 1.62 | 1.66 | 1.72 | 1.76 | 1.85 |
z percentile |
The given sample as
0.82 | 0.87 | 0.90 | 1.03 | 1.08 | 1.13 | 1.29 | 1.33 |
1.46 | 1.50 | 1.58 | 1.62 | 1.66 | 1.72 | 1.76 | 1.85 |
The Z score calculated as
S= Sample standard deviation=0.3418
X= variables
X-bar= Sample mean =1.35 calculated as
n=12
The Z percentile associated with observations are
Sample Observation | 0.82 | 0.87 | 0.9 | 1.03 | 1.08 | 1.13 | 1.29 | 1.33 | 1.46 | 1.5 | 1.58 | 1.62 | 1.66 | 1.72 | 1.76 | 1.85 |
Z score | -1.55035 | -1.40409 | -1.31634 | -0.93606 | -0.7898 | -0.64354 | -0.17551 | -0.0585 | 0.321771 | 0.438779 | 0.672794 | 0.789802 | 0.906809 | 1.082321 | 1.199328 | 1.462596 |
Z percentile | 0.060571. | 0.080159. | 0.094087 | 0.174637 | 0.215056 | 0.260112 | 0.430147 | 0.476476 | 0.62616 | 0.669561 | 0.749431 | 0.785178 | 0.817744 | 0.86044 | 0.884794 | 0.928198 |
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