You roll two six-sided fair dice.
a. Let A be the event that either a 3 or 4 is rolled first
followed by an odd number.
P(A) = Round your answer to four decimal places.
b. Let B be the event that the sum of the two dice is at most
7.
P(B) = Round your answer to four decimal places.
total outcomes of rolling two dice=6^2=36
possible outcomes of A( either a 3 or 4 is rolled first followed by an odd number) =6 (as shown below)
31 | 41 |
33 | 43 |
35 | 45 |
P(A) = 6/36 =1/6 = 0.1667
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total possible outcomes of B = 21 as shown below
sum is at most 7 (or < = 7)
1,1 | 2,1 | 3,1 | 4,1 | 5,1 | 6,1 |
1,2 | 2,2 | 3,2 | 4,2 | 5,2 | |
1,3 | 2,3 | 3,3 | 4,3 | ||
1,4 | 2,4 | 3,4 | |||
1,5 | 2,5 | ||||
1,6 |
P(B) = 21/36 =0.5833
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