The general manager of a chain of pharmaceutical stores reported the results of a regression analysis, designed to predict the annual sales for all the stores in the chain (Y) – measured in millions of dollars. One independent variable used to predict annual sales of stores is the size of the store (X) – measured in thousands of square feet. Data for 14 pharmaceutical stores were used to fit a linear model. The results of the simple linear regression are provided below.
Y = 0.964 + 1.670X; SYX =$0.9664 million; 2 – tailed p value = 0.00004 (for testing ß1);
Sb1=0.157; X = 2.9124; SSX=Σ( Xi –X )2=37.924; n=14 ;
Suppose the general manager wants to obtain a prediction interval estimate for the mean annual sales for
pharmaceutical stores that have a size of 4000 sq. feet. Compute this prediction interval:
(6.6710 , 10.9140) |
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(5.4330 , 9.8540) |
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(6.2130 , 9.8540) |
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(5.4330 , 10.8540) |
predcited value at X=4: | 7.64 | ||||
std error prediction interval= | s*√(1+1/n+(x0-x̅)2/Sxx) | = | 1.0148 | ||
for 95 % CI value of t= | 2.1790 | ||||
margin of error E=t*std error = | 2.21 | ||||
lower prediction bound=sample mean-margin of error = | 5.433 | ||||
Upper prediction bound=sample mean+margin of error= | 9.855 |
from above: correct option is : (5.4330 , 9.8540)
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