5. A telephone sales solicitor, trying to decide between two alternative sales pitches, randomly alternated between them during a day of calls. Using approach A, 20% of 100 calls led to requests for the mailing of additional product information. For approach B in another 100 calls, only 14 % led to requests for the product information mailing. At the 0.05 significance level, can we conlcude that the difference in results was due to chance? Construct the 95% confidence level for the difference between population proportions (π1 - π2). Identify and interpret the p-value for the test.
ANSWER FORMAT:
Define H0 : |
Define H1 : |
Test statistic |
Critical value of test statistic |
Decision rule |
Calculated value of test statistic |
Reject or fail to reject H0? |
Conclusion about differences in sales pitches |
95% confidence interval for difference between proportions |
Find the p-value |
Interpret p-value |
Answer:
Let denoes the proportion of requests for the mailing of additional product information
and denoes the proportion of requests for the product information mailing.
To test against
The test statistic is given by
which under H0 follows a standard normal distribution.
We reject H0 if |zobs|>z0.025
where
Here
p-value=2*P(Z>1.12946)=0.258704
So,we accept H0 at 5% level of significance and we can conclude that there is no significant difference between two proportions.
95% confidence interval for π1 - π2
=
=(-0.0441180,0.164118)
Thank you !
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